Difference between revisions of "Mock AIME 3 Pre 2005 Problems/Problem 12"
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− | We see a pattern when we look at the numbers that do fulfull this property. The first number is <math>1</math>. Then <math>3, 8, 9, 24, 27, ....</math>. This follows a pattern. The first number being <math>1</math>, and the rest being the previous <math>+2, +5, +1, +15, +3, +19, +3, +15, +1, +5, +2</math>. This sequence then repeats itself. We hence find that there are a total of <math>11*15 - 1</math> or <math>\boxed{164}</math> numbers that satisfy the inequality. | + | We see a pattern when we look at the numbers that do fulfull this property. The first number is <math>1</math>. Then <math>3, 8, 9, 24, 27, ....</math>. This follows a pattern. The first number being <math>1</math>, and the rest being the previous: <math>+2, +5, +1, +15, +3, +19, +3, +15, +1, +5, +2</math>. This sequence then repeats itself. We hence find that there are a total of <math>11*15 - 1</math> or <math>\boxed{164}</math> numbers that satisfy the inequality. |
==See also== | ==See also== |
Revision as of 17:19, 25 April 2009
Problem
Determine the number of integers such that and is divisible by .
Solution
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We see a pattern when we look at the numbers that do fulfull this property. The first number is . Then . This follows a pattern. The first number being , and the rest being the previous: . This sequence then repeats itself. We hence find that there are a total of or numbers that satisfy the inequality.