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Difference between revisions of "2005 AMC 12B Problems/Problem 1"

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== Problem ==
 
== Problem ==
−
Two is <math>10\%</math> of <math>x</math> and <math>20\%</math> of <math>y</math>.  What is <math>x-y</math>?
+
A scout troop buys <math>1000</math> candy bars at a price of five for <math>2</math> dollars. They sell all the candy bars at the price of two for <math>1</math> dollar.  What was their profit, in dollars?
  
 
<math>
 
<math>
−
\mathrm{(A)}\ 1     \qquad
+
\mathrm{(A)}\ 100     \qquad
−
\mathrm{(B)}\ 2     \qquad
+
\mathrm{(B)}\ 200     \qquad
−
\mathrm{(C)}\ 5     \qquad
+
\mathrm{(C)}\ 300     \qquad
−
\mathrm{(D)}\ 10     \qquad
+
\mathrm{(D)}\ 400     \qquad
−
\mathrm{(E)}\ 20
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\mathrm{(E)}\ 500
 
</math>
 
</math>
  

Revision as of 20:56, 17 April 2009

Problem

A scout troop buys $1000$ candy bars at a price of five for $2$ dollars. They sell all the candy bars at the price of two for $1$ dollar. What was their profit, in dollars?

$\mathrm{(A)}\ 100 \qquad \mathrm{(B)}\ 200 \qquad \mathrm{(C)}\ 300 \qquad \mathrm{(D)}\ 400 \qquad \mathrm{(E)}\ 500$

Solution

$2=0.1x \Rightarrow x=20$.

$2=0.2y \Rightarrow y=10$.

$\therefore x-y=20-10=\boxed{10}$.

See also

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