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Difference between revisions of "2005 AMC 12B Problems/Problem 2"

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== Solution ==
 
== Solution ==
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<math>2x+7=3 \Rightarrow 2x = -4 \Rightarrow = -2</math>.
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<math>-2b-10=-2 \Rightarrow -2b = 8 \Rightarrow b = \boxed{-4}</math>.
  
 
== See also ==
 
== See also ==
 
* [[2005 AMC 12B Problems]]
 
* [[2005 AMC 12B Problems]]

Revision as of 20:35, 17 April 2009

Problem

The equations $2x+7=3$ and $bx-10=-2$ have the same solution for $x$. What is the value of $b$?

$\mathrm{(A)}\ -8 \qquad \mathrm{(B)}\ -4 \qquad \mathrm{(C)}\ -2 \qquad \mathrm{(D)}\ 4 \qquad \mathrm{(E)}\ 8$

Solution

$2x+7=3 \Rightarrow 2x = -4 \Rightarrow = -2$.

$-2b-10=-2 \Rightarrow -2b = 8 \Rightarrow b = \boxed{-4}$.

See also

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