Difference between revisions of "1988 AJHSME Problems/Problem 24"
(New page: ==Problem== <asy> unitsize(15); for (int a=0; a<6; ++a) { draw(2*dir(60a)--2*dir(60a+60),linewidth(1)); } draw((1,1.7320508075688772935274463415059)--(1,3.732050807568877293527446341...) |
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==Problem== | ==Problem== | ||
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<asy> | <asy> | ||
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fill((.4,1.7320508075688772935274463415059)--(0,3.35)--(-.4,1.7320508075688772935274463415059)--cycle,black); | fill((.4,1.7320508075688772935274463415059)--(0,3.35)--(-.4,1.7320508075688772935274463415059)--cycle,black); | ||
label("1.",(0,-2),S); | label("1.",(0,-2),S); | ||
+ | draw(arc((1,1.7320508075688772935274463415059),1,90,300,CW)); | ||
+ | draw((1.5,0.86602540378443864676372317075294)--(1.75,1.7)); | ||
+ | draw((1.5,0.86602540378443864676372317075294)--(2.2,1)); | ||
draw((7,0)--(6,1.7320508075688772935274463415059)--(4,1.7320508075688772935274463415059)--(3,0)--(4,-1.7320508075688772935274463415059)--(6,-1.7320508075688772935274463415059)--cycle,linewidth(1)); | draw((7,0)--(6,1.7320508075688772935274463415059)--(4,1.7320508075688772935274463415059)--(3,0)--(4,-1.7320508075688772935274463415059)--(6,-1.7320508075688772935274463415059)--cycle,linewidth(1)); | ||
draw((7,0)--(6,1.7320508075688772935274463415059)--(7.7320508075688772935274463415059,2.7320508075688772935274463415059)--(8.7320508075688772935274463415059,1)--cycle,linewidth(1)); | draw((7,0)--(6,1.7320508075688772935274463415059)--(7.7320508075688772935274463415059,2.7320508075688772935274463415059)--(8.7320508075688772935274463415059,1)--cycle,linewidth(1)); | ||
label("2.",(5,-2),S); | label("2.",(5,-2),S); | ||
+ | draw(arc((7,0),1,30,240,CW)); | ||
+ | draw((6.5,-0.86602540378443864676372317075294)--(7.1,-.7)); | ||
+ | draw((6.5,-0.86602540378443864676372317075294)--(6.8,-1.5)); | ||
draw((14,0)--(13,1.7320508075688772935274463415059)--(11,1.7320508075688772935274463415059)--(10,0)--(11,-1.7320508075688772935274463415059)--(13,-1.7320508075688772935274463415059)--cycle,linewidth(1)); | draw((14,0)--(13,1.7320508075688772935274463415059)--(11,1.7320508075688772935274463415059)--(10,0)--(11,-1.7320508075688772935274463415059)--(13,-1.7320508075688772935274463415059)--cycle,linewidth(1)); | ||
draw((14,0)--(13,-1.7320508075688772935274463415059)--(14.7320508075688772935274463415059,-2.7320508075688772935274463415059)--(15.7320508075688772935274463415059,-1)--cycle,linewidth(1)); | draw((14,0)--(13,-1.7320508075688772935274463415059)--(14.7320508075688772935274463415059,-2.7320508075688772935274463415059)--(15.7320508075688772935274463415059,-1)--cycle,linewidth(1)); |
Revision as of 16:25, 14 April 2009
Problem
The square in the first diagram "rolls" clockwise around the fixed regular hexagon until it reaches the bottom. In which position will the solid triangle be in diagram ?
Solution
The triangle's point rotates as well as the square. Common sense tells us that in diagram 4, the triangle will be upside down. So C.