Difference between revisions of "2006 AMC 12B Problems/Problem 7"
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| Line 9: | Line 9: | ||
First, we seat the children. | First, we seat the children. | ||
| − | The first child can be seated in 3 spaces. | + | The first child can be seated in <math>3</math> spaces. |
| − | The second child can be seated in 2 spaces. | + | The second child can be seated in <math>2</math> spaces. |
| − | Now there are 2 | + | Now there are <math>2 \times 1</math> ways to seat the adults. |
| − | <math>3 | + | <math>3 \times 2 \times 2 = 12 \Rightarrow \text{(B)}</math> |
== See also == | == See also == | ||
{{AMC12 box|year=2006|ab=B|num-b=6|num-a=8}} | {{AMC12 box|year=2006|ab=B|num-b=6|num-a=8}} | ||
Revision as of 19:03, 29 January 2009
Problem
Mr. and Mrs. Lopez have two children. When they get into their family car, two people sit in the front, and the other two sit in the back. Either Mr. Lopez or Mrs. Lopez must sit in the driver's seat. How many seating arrangements are possible?
Solution
First, we seat the children.
The first child can be seated in 
spaces.
The second child can be seated in 
spaces.
Now there are 
ways to seat the adults.
See also
| 2006 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 6 |
Followed by Problem 8 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
