Difference between revisions of "1985 AJHSME Problems/Problem 6"
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==Solution== | ==Solution== | ||
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We could solve the first equation for the thickness of one sheet of paper, and divide into the 2nd equation (which is one way to do the problem), but there are other ways, too. | We could solve the first equation for the thickness of one sheet of paper, and divide into the 2nd equation (which is one way to do the problem), but there are other ways, too. | ||
| − | Let's say that <math>\frac{500 sheets of paper}{5 cm} = 1</math>. So by multiplying <math>7.5 cm</math> by this fraction, we SHOULD get the number of sheets in 7.5 cm. Solving gets | + | Let's say that <math>\frac{500 \text{ sheets of paper}}{5 \text{ cm}} = 1</math>. So by multiplying <math>7.5 \text{ cm}</math> by this fraction, we SHOULD get the number of sheets in 7.5 cm. Solving gets |
| − | < | + | <cmath>\begin{align*} |
| + | \frac{7.5 \times 500}{5} &= 7.5 \times 100 \\ | ||
| + | &= 750 sheets \\ | ||
| + | \end{align*}</cmath> | ||
| − | <math>750</math> is | + | <math>750</math> is <math>\boxed{\text{D}}</math> |
==See Also== | ==See Also== | ||
[[1985 AJHSME Problems]] | [[1985 AJHSME Problems]] | ||
Revision as of 21:36, 12 January 2009
Problem
A ream of paper containing 
sheets is 
cm thick. Approximately how many sheets of this type of paper would there be in a stack 
cm high?
Solution
We could solve the first equation for the thickness of one sheet of paper, and divide into the 2nd equation (which is one way to do the problem), but there are other ways, too.
Let's say that 
. So by multiplying 
by this fraction, we SHOULD get the number of sheets in 7.5 cm. Solving gets
is 
