Difference between revisions of "2006 AMC 10A Problems/Problem 3"

Latest revision as of 23:03, 27 April 2008

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-== Problem ==
+#redirect [[2006 AMC 12A Problems/Problem 3]]
-The ratio of Mary's age to Alice's age is 3:5.  Alice is 30 years old.  How many years old is Mary?
-<math> \mathrm{(A) \ } 15\qquad \mathrm{(B) \ } 18\qquad \mathrm{(C) \ } 20\qquad \mathrm{(D) \ } 24\qquad \mathrm{(E) \ } 50 </math>
-== Solution ==
-We can create the equation
-<math>\frac{3}{5}=\frac{x}{30}</math>
-Where ''x'' is Mary's age. Simplfying yields
-<math>(3)(30)=5x\Longrightarrow 90=5x\Longrightarrow x=18, (B)</math>
-== See also ==
-{{AMC10 box|year=2006|ab=A|num-b=2|num-a=4}}
-[[Category:Introductory Algebra Problems]]