Difference between revisions of "2008 AMC 10B Problems/Problem 1"

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==Solution==
 
==Solution==
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The number of points could have been 10, 11, 12, 13, 14, or 15. Thus, the answer is <math>\mathrm{(E)}</math>.
  
 
==See also==
 
==See also==
 
{{AMC10 box|year=2008|ab=B|before=First Question|num-a=2}}
 
{{AMC10 box|year=2008|ab=B|before=First Question|num-a=2}}

Revision as of 01:43, 25 April 2008

Problem

A basketball player made 5 baskets during a game. Each basket was worth either 2 or 3 points. How many different numbers could represent the total points scored by the player?

$\mathrm{(A)}\ 2\qquad\mathrm{(B)}\ 3\qquad\mathrm{(C)}\ 4\qquad\mathrm{(D)}\ 5\qquad\mathrm{(E)}\ 6$

Solution

The number of points could have been 10, 11, 12, 13, 14, or 15. Thus, the answer is $\mathrm{(E)}$.

See also

2008 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions