Difference between revisions of "2018 AMC 8 Problems/Problem 16"

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==Problem 16==
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==Problem==
 
Professor Chang has nine different language books lined up on a bookshelf: two Arabic, three German, and four Spanish. How many ways are there to arrange the nine books on the shelf keeping the Arabic books together and keeping the Spanish books together?
 
Professor Chang has nine different language books lined up on a bookshelf: two Arabic, three German, and four Spanish. How many ways are there to arrange the nine books on the shelf keeping the Arabic books together and keeping the Spanish books together?
  
 
<math>\textbf{(A) }1440\qquad\textbf{(B) }2880\qquad\textbf{(C) }5760\qquad\textbf{(D) }182,440\qquad \textbf{(E) }362,880</math>
 
<math>\textbf{(A) }1440\qquad\textbf{(B) }2880\qquad\textbf{(C) }5760\qquad\textbf{(D) }182,440\qquad \textbf{(E) }362,880</math>
  
==Solution==
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=Solution=
Since the Arabic books and Spanish books have to by kept together, we can treat them both as just one book. That means we're trying to find the number of ways you can arrange one Arabic book, one Spanish book, and three German books, which is just <math>5</math> factorial. Now we multiply this product by <math>2!</math> because there are <math>2</math> factorial ways to arrange just the Arabic books, and <math>4!</math> ways to arrange just the Spanish books. Multiplying all these together, we have <math>2!\cdot 4!\cdot 5!=\boxed{\textbf{(C) }5760}</math>.
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To solve this, treat the two Arabic books as one unit and the four Spanish books as another unit. Along with the three German books, you now have five units to arrange.
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You can arrange these five units in <math>5!</math> ways. Within the Arabic block, the two books can be arranged in <math>2!</math> ways, and within the Spanish block, the four books can be arranged in <math>4!</math> ways.
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Multiplying all these possibilities gives the total number of arrangements which is <math>\boxed{\textbf{(C) }5,760}.</math> ways to arrange the nine books while keeping the Arabic and Spanish books together.
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==Video Solution (Pls Subscribe if you watch 🙏🙏🙏🥺🥺🥺)==
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https://youtu.be/HqeNT9ctfUo
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~EzLx
  
 
==See Also==
 
==See Also==

Latest revision as of 11:55, 21 January 2025

Problem

Professor Chang has nine different language books lined up on a bookshelf: two Arabic, three German, and four Spanish. How many ways are there to arrange the nine books on the shelf keeping the Arabic books together and keeping the Spanish books together?

$\textbf{(A) }1440\qquad\textbf{(B) }2880\qquad\textbf{(C) }5760\qquad\textbf{(D) }182,440\qquad \textbf{(E) }362,880$

Solution

To solve this, treat the two Arabic books as one unit and the four Spanish books as another unit. Along with the three German books, you now have five units to arrange.

You can arrange these five units in $5!$ ways. Within the Arabic block, the two books can be arranged in $2!$ ways, and within the Spanish block, the four books can be arranged in $4!$ ways.

Multiplying all these possibilities gives the total number of arrangements which is $\boxed{\textbf{(C) }5,760}.$ ways to arrange the nine books while keeping the Arabic and Spanish books together.


Video Solution (Pls Subscribe if you watch 🙏🙏🙏🥺🥺🥺)

https://youtu.be/HqeNT9ctfUo

~EzLx

See Also

2018 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 15
Followed by
Problem 17
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All AJHSME/AMC 8 Problems and Solutions

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