Difference between revisions of "2025 AMC 8 Problems/Problem 9"

Latest revision as of 18:16, 20 December 2024

The 2025 AMC 8 is not held yet. Please do not post false problems.

Revision as of 08:33, 23 February 2024 (view source) Theumbrellaacademy (talk \| contribs) (2025 AMC 8 Problem 9) ← Older edit		Latest revision as of 18:16, 20 December 2024 (view source) LauraZed (talk \| contribs) m (Protected "2025 AMC 8 Problems/Problem 9" ([Edit=Allow only administrators] (expires 17:59, 29 January 2025 (UTC)) [Move=Allow only administrators] (expires 17:59, 29 January 2025 (UTC))))
(One intermediate revision by one other user not shown)
Line 1:		Line 1:
−	~~There are <math>10</math> matchsticks on the table~~. ~~Percy takes <math>1</math>, <math>2</math> or <math>3</math> matchsticks each time~~. ~~How many ways are there for him to take all the matchsticks?~~	+	The 2025 AMC 8 is not held yet. Please do not post false problems.
−
−	~~<math>\textbf{(A)}\ 274 \qquad \textbf{(B)}\ 275 \qquad \textbf{(C)}\ 276 \qquad \textbf{(D)}\ 280 \qquad \textbf{(E)}\ 295</math>~~