Difference between revisions of "2010 AMC 8 Problems/Problem 6"
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==Solution== | ==Solution== | ||
− | An equilateral triangle has 3 lines of symmetry. | + | An equilateral triangle has <math>3</math> lines of symmetry. |
− | A non-square rhombus has 2 lines of symmetry. | + | A non-square rhombus has <math>2</math> lines of symmetry. |
− | A non-square rectangle has 2 lines of symmetry. | + | A non-square rectangle has <math>2</math> lines of symmetry. |
− | An isosceles trapezoid has 1 line of symmetry. | + | An isosceles trapezoid has <math>1</math> line of symmetry. |
− | A square has 4 lines of symmetry. | + | A square has <math>4</math> lines of symmetry. |
Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>. | Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>. | ||
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+ | ==Video Solution by @MathTalks== | ||
+ | https://youtu.be/RhyRqHMXvq0?si=m1R2q8UnLRD-KksT | ||
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+ | ==Video Solution by WhyMath== | ||
+ | https://youtu.be/hoZO5M0raTI | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2010|num-b=5|num-a=7}} | {{AMC8 box|year=2010|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 10:25, 18 November 2024
Problem
Which of the following figures has the greatest number of lines of symmetry?
Solution
An equilateral triangle has lines of symmetry. A non-square rhombus has lines of symmetry. A non-square rectangle has lines of symmetry. An isosceles trapezoid has line of symmetry. A square has lines of symmetry.
Therefore, the answer is .
Video Solution by @MathTalks
https://youtu.be/RhyRqHMXvq0?si=m1R2q8UnLRD-KksT
Video Solution by WhyMath
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.