Difference between revisions of "2024 AMC 10B Problems/Problem 24"
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<math>\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4</math> | <math>\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4</math> | ||
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==See also== | ==See also== | ||
{{AMC10 box|year=2024|ab=B|num-b=23|num-a=25}} | {{AMC10 box|year=2024|ab=B|num-b=23|num-a=25}} | ||
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{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 05:54, 14 November 2024
Problem
Let
![\[P(m)=\frac{m}{2}+\frac{m^2}{4}+\frac{m^4}{8}+\frac{m^8}{8}\]](http://latex.artofproblemsolving.com/2/b/f/2bfe40a41fdb136435709353d32dbe9a87331a66.png)
How many of the values 
, 
, 
, and 
are integers?
Solution
See also
| 2024 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
