Difference between revisions of "2003 AMC 8 Problems/Problem 2"
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==Solution== | ==Solution== | ||
The smallest prime factor is <math> 2 </math>, and since <math> 58 </math> is the only multiple of <math> 2 </math>, the answer is <math> \boxed{\mathrm{(C)}\ 58} </math>. | The smallest prime factor is <math> 2 </math>, and since <math> 58 </math> is the only multiple of <math> 2 </math>, the answer is <math> \boxed{\mathrm{(C)}\ 58} </math>. | ||
| + | |||
| + | == Video Solution by OmegaLearn == | ||
| + | https://youtu.be/7an5wU9Q5hk?t=152 | ||
| + | |||
| + | ~ pi_is_3.14 | ||
| + | |||
| + | ==Video Solution== | ||
| + | https://youtu.be/7an5wU9Q5hk?t=152 | ||
| + | |||
| + | ==See Also== | ||
| + | {{AMC8 box|year=2003|num-b=1|num-a=3}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 00:42, 17 October 2024
Problem
Which of the following numbers has the smallest prime factor?
Solution
The smallest prime factor is 
, and since 
is the only multiple of , the answer is 
.
Video Solution by OmegaLearn
https://youtu.be/7an5wU9Q5hk?t=152
~ pi_is_3.14
Video Solution
https://youtu.be/7an5wU9Q5hk?t=152
See Also
| 2003 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
