Difference between revisions of "1982 AHSME Problems/Problem 6"
Duck master (talk | contribs) (created page w/ solution & categorization) |
Tecilis459 (talk | contribs) m (Add title) |
||
Line 1: | Line 1: | ||
+ | == Problem == | ||
+ | |||
The sum of all but one of the interior angles of a convex polygon equals <math>2570^\circ</math>. The remaining angle is | The sum of all but one of the interior angles of a convex polygon equals <math>2570^\circ</math>. The remaining angle is | ||
Latest revision as of 12:27, 16 July 2024
Problem
The sum of all but one of the interior angles of a convex polygon equals . The remaining angle is
Solution
Note that the sum of the interior angles of a convex polygon of sides is , and each interior angle belongs to . Therefore, we must have . Then the missing angle must be , so our answer is and we are done.
See also
1982 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.