Difference between revisions of "2002 AMC 12P Problems/Problem 23"
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== Solution == | == Solution == | ||
+ | Note that <math>2002 = 11 \cdot 13 \cdot 14</math>. | ||
According to Wolfram-Alpha, the answer is <math>\boxed {\text{(A) }\sqrt{118}}</math>. | According to Wolfram-Alpha, the answer is <math>\boxed {\text{(A) }\sqrt{118}}</math>. | ||
Revision as of 16:38, 1 July 2024
Problem
The equation has a zero of the form , where and are positive real numbers. Find
Solution
Note that . According to Wolfram-Alpha, the answer is .
See also
2002 AMC 12P (Problems • Answer Key • Resources) | |
Preceded by Problem 22 |
Followed by Problem 24 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.