Difference between revisions of "1972 AHSME Problems"

Latest revision as of 23:21, 25 May 2024

1972 AHSC (Answer Key) Printable versions: Wiki • AoPS Resources • PDF
Instructions This is a 35-question, multiple choice test. Each question is followed by answers marked A, B, C, D and E. Only one of these is correct. You will receive ? points for each correct answer, ? points for each problem left unanswered, and ? points for each incorrect answer. No aids are permitted other than scratch paper, graph paper, ruler, compass, protractor and erasers. Figures are not necessarily drawn to scale. You will have ? minutes working time to complete the test.
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35

Problem 1

The lengths in inches of the three sides of each of four triangles $I, II, III$ , and $IV$ are as follows:

$\begin{array}{rlrl} \hbox{I}& 3,\ 4,\ \hbox{and}\ 5\qquad & \hbox{III}& 7,\ 24,\ \hbox{and}\ 25\\ \hbox{II}& 4,\ 7\frac{1}{2},\ \hbox{and}\ 8\frac{1}{2}\qquad & \hbox{IV}& 3\frac{1}{2},\ 4\frac{1}{2},\ \hbox{and}\ 5\frac{1}{2}.\end{array}$

Of these four given triangles, the only right triangles are

$\text{(A) I and II}\qquad \text{(B) I and III}\qquad \text{(C) I and IV} \quad \\ \text{(D) I, II, and III} \qquad \text{(E) I, II, and IV }$

Solution

Problem 2

If a dealer could get his goods for $8$ % less while keeping his selling price fixed, his profit, based on cost, would be increased to $(x+10)$ % from his present profit of $x$ %, which is

$\textbf{(A) }12\%\qquad \textbf{(B) }15\%\qquad \textbf{(C) }30\%\qquad \textbf{(D) }50\%\qquad \textbf{(E) }75\%$

Solution

Problem 3

If $x=\dfrac{1-i\sqrt{3}}{2}$ where $i=\sqrt{-1}$ , then $\dfrac{1}{x^2-x}$ is equal to

$\textbf{(A) }-2\qquad \textbf{(B) }-1\qquad \textbf{(C) }1+i\sqrt{3}\qquad \textbf{(D) }1\qquad \textbf{(E) }2$

Solution

Problem 4

The number of solutions to $\{1,~2\}\subseteq~X~\subseteq~\{1,~2,~3,~4,~5\}$ , where $X$ is a subset of $\{1,~2,~3,~4,~5\}$ is

$\textbf{(A) }2\qquad \textbf{(B) }4\qquad \textbf{(C) }6\qquad \textbf{(D) }8\qquad \textbf{(E) }\text{None of these}$

Solution

Problem 5

From among $2^{1/2}, 3^{1/3}, 8^{1/8}, 9^{1/9}$ those which have the greatest and the next to the greatest values, in that order, are

$\textbf{(A) } 3^{1/3},\ 2^{1/2}\quad \textbf{(B) } 3^{1/3},\ 8^{1/8}\quad \textbf{(C) } 3^{1/3},\ 9^{1/9}\quad \textbf{(D) } 8^{1/8},\ 9^{1/9}\quad \\ \text{(E) None of these}$

Solution

Problem 6

If $3^{2x}+9=10\left(3^{x}\right)$ , then the value of $(x^2+1)$ is

$\textbf{(A) }1\text{ only}\qquad \textbf{(B) }5\text{ only}\qquad \textbf{(C) }1\text{ or }5\qquad \textbf{(D) }2\qquad \textbf{(E) }10$

Solution

Problem 7

If $yz:zx:xy=1:2:3$ , then $\dfrac{x}{yz}:\dfrac{y}{zx}$ is equal to

$\textbf{(A) }3:2\qquad \textbf{(B) }1:2\qquad \textbf{(C) }1:4\qquad \textbf{(D) }2:1\qquad \textbf{(E) }4:1$

Solution

Problem 8

If $|x-\log y|=x+\log y$ where $x$ and $\log y$ are real, then

$\textbf{(A) }x=0\qquad \textbf{(B) }y=1\qquad \textbf{(C) }x=0\text{ and }y=1\qquad\\ \textbf{(D) }x(y-1)=0\qquad \textbf{(E) }\text{None of these}$

Solution

Problem 9

Ann and Sue bought identical boxes of stationery. Ann used hers to write $1$ -sheet letters and Sue used hers to write $3$ -sheet letters. Ann used all the envelopes and had $50$ sheets of paper left, while Sue used all of the sheets of paper and had $50$ envelopes left. The number of sheets of paper in each box was

$\textbf{(A) } 150 \qquad \textbf{(B) } 125 \qquad \textbf{(C) } 120 \qquad \textbf{(D) } 100 \qquad \textbf{(E) } 80 \qquad$

Solution

Problem 10

For $x$ real, the inequality $1\le |x-2|\le 7$ is equivalent to

$\textbf{(A) }x\le 1\text{ or }x\ge 3\qquad \textbf{(B) }1\le x\le 3\qquad \textbf{(C) }-5\le x\le 9\qquad \\ \textbf{(D) }-5\le x\le 1\text{ or }3\le x\le 9\qquad \textbf{(E) }-6\le x\le 1\text{ or }3\le x\le 10$

Solution

Problem 11

The value(s) of $y$ for which the following pair of equations $x^2+y^2+16=0\text{ and }x^2-3y+12=0$ may have a real common solution, are

$\textbf{(A) }4\text{ only}\qquad \textbf{(B) }-7,~4\qquad \textbf{(C) }0,~4\qquad \textbf{(D) }\text{no }y\qquad \textbf{(E) }\text{all }y$

Solution

Problem 12

The number of cubic feet in the volume of a cube is the same as the number of square inches in its surface area. The length of the edge expressed as a number of feet is

$\textbf{(A) }6\qquad \textbf{(B) }864\qquad \textbf{(C) }1728\qquad \textbf{(D) }6\times 1728\qquad \textbf{(E) }2304$

Solution

Problem 13

$[asy] draw(unitsquare);draw((0,0)--(.4,1)^^(0,.6)--(1,.2)); label("D",(0,1),NW);label("E",(.4,1),N);label("C",(1,1),NE); label("P",(0,.6),W);label("M",(.25,.55),E);label("Q",(1,.2),E); label("A",(0,0),SW);label("B",(1,0),SE); //Credit to Zimbalono for the diagram [/asy]$

Inside square $ABCD$ (See figure) with sides of length $12$ inches, segment $AE$ is drawn where $E$ is the point on $DC$ which is $5$ inches from $D$ . The perpendicular bisector of $AE$ is drawn and intersects $AE, AD$ , and $BC$ at points $M, P$ , and $Q$ respectively. The ratio of segment $PM$ to $MQ$ is

$\textbf{(A) }5:12\qquad \textbf{(B) }5:13\qquad \textbf{(C) }5:19\qquad \textbf{(D) }1:4\qquad \textbf{(E) }5:21$

Solution

Problem 14

A triangle has angles of $30^\circ$ and $45^\circ$ . If the side opposite the $45^\circ$ angle has length $8$ , then the side opposite the $30^\circ$ angle has length

$\textbf{(A) }4\qquad \textbf{(B) }4\sqrt{2}\qquad \textbf{(C) }4\sqrt{3}\qquad \textbf{(D) }4\sqrt{6}\qquad \textbf{(E) }6$

Solution

Problem 15

A contractor estimated that one of his two bricklayers would take $9$ hours to build a certain wall and the other $10$ hours. However, he knew from experience that when they worked together, their combined output fell by $10$ bricks per hour. Being in a hurry, he put both men on the job and found that it took exactly 5 hours to build the wall. The number of bricks in the wall was

$\textbf{(A) }500\qquad \textbf{(B) }550\qquad \textbf{(C) }900\qquad \textbf{(D) }950\qquad \textbf{(E) }960$

Solution

Problem 16

There are two positive numbers that may be inserted between $3$ and $9$ such that the first three are in geometric progression while the last three are in arithmetic progression. The sum of those two positive numbers is

$\textbf{(A) }13\textstyle\frac{1}{2}\qquad \textbf{(B) }11\frac{1}{4}\qquad \textbf{(C) }10\frac{1}{2}\qquad \textbf{(D) }10\qquad \textbf{(E) }9\frac{1}{2}$

Solution

Problem 17

A piece of string is cut in two at a point selected at random. The probability that the longer piece is at least x times as large as the shorter piece is

$\textbf{(A) }\frac{1}{2}\qquad \textbf{(B) }\frac{2}{x}\qquad \textbf{(C) }\frac{1}{x+1}\qquad \textbf{(D) }\frac{1}{x}\qquad \textbf{(E) }\frac{2}{x+1}$

Solution

Problem 18

Let $ABCD$ be a trapezoid with the measure of base $AB$ twice that of base $DC$ , and let $E$ be the point of intersection of the diagonals. If the measure of diagonal $AC$ is $11$ , then that of segment $EC$ is equal to

$\textbf{(A) }3\textstyle\frac{2}{3}\qquad \textbf{(B) }3\frac{3}{4}\qquad \textbf{(C) }4\qquad \textbf{(D) }3\frac{1}{2}\qquad \textbf{(E) }3$

Solution

Problem 19

The sum of the first $n$ terms of the sequence $1,~(1+2),~(1+2+2^2),~\dots ~(1+2+2^2+\dots +2^{n-1})$ in terms of $n$ is

$\textbf{(A) }2^n\qquad \textbf{(B) }2^n-n\qquad \textbf{(C) }2^{n+1}-n\qquad \textbf{(D) }2^{n+1}-n-2\qquad \textbf{(E) }n\cdot 2^n$

Solution

Problem 20

If $\tan x=\dfrac{2ab}{a^2-b^2}$ where $a>b>0$ and $0^\circ <x<90^\circ$ , then $\sin x$ is equal to

$\textbf{(A) }\frac{a}{b}\qquad \textbf{(B) }\frac{b}{a}\qquad \textbf{(C) }\frac{\sqrt{a^2-b^2}}{2a}\qquad \textbf{(D) }\frac{\sqrt{a^2-b^2}}{2ab}\qquad \textbf{(E) }\frac{2ab}{a^2+b^2}$

Solution

Problem 21

$[asy] draw((3,-13)--(21.5,-5)--(19,-18)--(9,-18)--(10,-6)--(23,-14.5)--cycle); label("A",(3,-13),W);label("C",(21.5,-5),N);label("E",(19,-18),E);label("F",(9,-18),W);label("B",(10,-6),N);label("D",(23,-14.5),E); //Credit to Zimbalono for the diagram[/asy]$

If the sum of the measures in degrees of angles $A,~B,~C,~D,~E$ and $F$ in the figure above is $90n$ , then $n$ is equal to

$\textbf{(A) }2\qquad \textbf{(B) }3\qquad \textbf{(C) }4\qquad \textbf{(D) }5\qquad \textbf{(E) }6$

Solution

Problem 22

If $a\pm bi~(b\neq 0)$ are imaginary roots of the equation $x^3+qx+r=0$ where $a,~b,~q$ , and $r$ are real numbers, then $q$ in terms of $a$ and $b$ is

$\textbf{(A) }a^2+b^2\qquad \textbf{(B) }2a^2-b^2\qquad \textbf{(C) }b^2-a^2\qquad \textbf{(D) }b^2-2a^2\qquad \textbf{(E) }b^2-3a^2$

Solution

Problem 23

$[asy] draw((0,0)--(0,1)--(2,1)--(2,0)--cycle^^(.5,1)--(.5,2)--(1.5,2)--(1.5,1)--cycle^^(1,2)--(1,0)); [/asy]$

The radius of the smallest circle containing the symmetric figure composed of the 3 unit squares shown above is

$\textbf{(A) }\sqrt{2}\qquad \textbf{(B) }\sqrt{1.25}\qquad \textbf{(C) }1.25\qquad \textbf{(D) }\frac{5\sqrt{17}}{16}\qquad \textbf{(E) }\text{None of these}$

Solution

Problem 24

A man walked a certain distance at a constant rate. If he had gone $\textstyle\frac{1}{2}$ mile per hour faster, he would have walked the distance in four-fifths of the time; if he had gone $\textstyle\frac{1}{2}$ mile per hour slower, he would have been $2\textstyle\frac{1}{2}$ hours longer on the road. The distance in miles he walked was

$\textbf{(A) }13\textstyle\frac{1}{2}\qquad \textbf{(B) }15\qquad \textbf{(C) }17\frac{1}{2}\qquad \textbf{(D) }20\qquad \textbf{(E) }25$

Solution

Problem 25

Inscribed in a circle is a quadrilateral having sides of lengths $25,~39,~52$ , and $60$ taken consecutively. The diameter of this circle has length

$\textbf{(A) }62\qquad \textbf{(B) }63\qquad \textbf{(C) }65\qquad \textbf{(D) }66\qquad \textbf{(E) }69$

Solution

Problem 26

$[asy] real t=pi/8;real u=7*pi/12;real v=13*pi/12; real ct=cos(t);real st=sin(t);real cu=cos(u);real su=sin(u); draw(unitcircle); draw((ct,st)--(-ct,st)--(cos(v),sin(v))); draw((cu,su)--(cu,st)); label("A",(-ct,st),W);label("B",(ct,st),E); label("M",(cu,su),N);label("P",(cu,st),S); label("C",(cos(v),sin(v)),W); //Credit to Zimbalono for the diagram [/asy]$

In the circle above, $M$ is the midpoint of arc $CAB$ and segment $MP$ is perpendicular to chord $AB$ at $P$ . If the measure of chord $AC$ is $x$ and that of segment $AP$ is $(x+1)$ , then segment $PB$ has measure equal to

$\textbf{(A) }3x+2\qquad \textbf{(B) }3x+1\qquad \textbf{(C) }2x+3\qquad \textbf{(D) }2x+2\qquad \textbf{(E) }2x+1$

Solution

Problem 27

If the area of $\triangle ABC$ is $64$ square units and the geometric mean (mean proportional) between sides $AB$ and $AC$ is $12$ inches, then $\sin A$ is equal to

$\textbf{(A) }\dfrac{\sqrt{3}}{2}\qquad \textbf{(B) }\frac{3}{5}\qquad \textbf{(C) }\frac{4}{5}\qquad \textbf{(D) }\frac{8}{9}\qquad \textbf{(E) }\frac{15}{17}$

Solution

Problem 28

A circular disc with diameter $D$ is placed on an $8\times 8$ checkerboard with width $D$ so that the centers coincide. The number of checkerboard squares which are completely covered by the disc is

$\textbf{(A) }48\qquad \textbf{(B) }44\qquad \textbf{(C) }40\qquad \textbf{(D) }36\qquad \textbf{(E) }32$

Solution

Problem 29

If $f(x)=\log \left(\frac{1+x}{1-x}\right)$ for $-1<x<1$ , then $f\left(\frac{3x+x^3}{1+3x^2}\right)$ in terms of $f(x)$ is

$\textbf{(A) }-f(x)\qquad \textbf{(B) }2f(x)\qquad \textbf{(C) }3f(x)\qquad \textbf{(D) }\left[f(x)\right]^2\qquad \\ \textbf{(E) }[f(x)]^3-f(x)$

Solution

Problem 30

$[asy] real h = 7; real t = asin(6/h)/2; real x = 6-h*tan(t); real y = x*tan(2*t); draw((0,0)--(0,h)--(6,h)--(x,0)--cycle); draw((x,0)--(0,y)--(6,h)); draw((6,h)--(6,0)--(x,0),dotted); label("L",(3.75,h/2),W); label("$\theta$",(6,h-1.5),W);draw(arc((6,h),2,270,270-degrees(t)),Arrow(2mm)); label("6''",(3,0),S); draw((2.5,-.5)--(0,-.5),Arrow(2mm)); draw((3.5,-.5)--(6,-.5),Arrow(2mm)); draw((0,-.25)--(0,-.75));draw((6,-.25)--(6,-.75)); //Credit to Zimbalono for the diagram [/asy]$

A rectangular piece of paper 6 inches wide is folded as in the diagram so that one corner touches the opposite side. The length in inches of the crease L in terms of angle $\theta$ is

$\textbf{(A) }3\sec ^2\theta\csc\theta\qquad \textbf{(B) }6\sin\theta\sec\theta\qquad \textbf{(C) }3\sec\theta\csc\theta\qquad \textbf{(D) }6\sec\theta\csc^2\theta\qquad \textbf{(E) }\text{None of these}$

Solution

Problem 31

When the number $2^{1000}$ is divided by $13$ , the remainder in the division is

$\textbf{(A) }1\qquad \textbf{(B) }2\qquad \textbf{(C) }3\qquad \textbf{(D) }7\qquad \textbf{(E) }11$

Solution

Problem 32

$[asy] real t=pi/12;real u=8*t; real cu=cos(u);real su=sin(u); draw(unitcircle); draw((cos(-t),sin(-t))--(cos(13*t),sin(13*t))); draw((cu,su)--(cu,-su)); label("A",(cos(13*t),sin(13*t)),W); label("B",(cos(-t),sin(-t)),E); label("C",(cu,su),N); label("D",(cu,-su),S); label("E",(cu,sin(-t)),NE); label("2",((cu-1)/2,sin(-t)),N); label("6",((cu+1)/2,sin(-t)),N); label("3",(cu,(sin(-t)-su)/2),E); //Credit to Zimbalono for the diagram[/asy]$

Chords $AB$ and $CD$ in the circle above intersect at E and are perpendicular to each other. If segments $AE, EB$ , and $ED$ have measures $2, 3$ , and $6$ respectively, then the length of the diameter of the circle is

$\textbf{(A) }4\sqrt{5}\qquad \textbf{(B) }\sqrt{65}\qquad \textbf{(C) }2\sqrt{17}\qquad \textbf{(D) }3\sqrt{7}\qquad \textbf{(E) }6\sqrt{2}$

Solution

Problem 33

The minimum value of the quotient of a (base ten) number of three different non-zero digits divided by the sum of its digits is

$\textbf{(A) }9.7\qquad \textbf{(B) }10.1\qquad \textbf{(C) }10.5\qquad \textbf{(D) }10.9\qquad \textbf{(E) }20.5$

Solution

Problem 34

Three times Dick's age plus Tom's age equals twice Harry's age. Double the cube of Harry's age is equal to three times the cube of Dick's age added to the cube of Tom's age. Their respective ages are relatively prime to each other. The sum of the squares of their ages is

$\textbf{(A) }42\qquad \textbf{(B) }46\qquad \textbf{(C) }122\qquad \textbf{(D) }290\qquad \textbf{(E) }326$

Solution

Problem 35

$[asy] draw(unitsquare);draw((0,0)--(.25,sqrt(3)/4)--(.5,0)); label("Z",(0,1),NW);label("Y",(1,1),NE);label("A",(0,0),SW);label("X",(1,0),SE);label("B",(.5,0),S);label("P",(.25,sqrt(3)/4),N); //Credit to Zimbalono for the diagram [/asy]$

Equilateral triangle $ABP$ (see figure) with side $AB$ of length $2$ inches is placed inside square $AXYZ$ with side of length $4$ inches so that $B$ is on side $AX$ . The triangle is rotated clockwise about $B$ , then $P$ , and so on along the sides of the square until $P$ returns to its original position. The length of the path in inches traversed by vertex $P$ is equal to

$\textbf{(A) }20\pi/3\qquad \textbf{(B) }32\pi/3\qquad \textbf{(C) }12\pi\qquad \textbf{(D) }40\pi/3\qquad \textbf{(E) }15\pi$

Solution

@@ Line 1: / Line 1: @@
+{{AHSC 35 Problems
+|year = 1972
+}}
 == Problem 1 ==
@@ Line 11: / Line 14: @@
 Of these four given triangles, the only right triangles are
-<math>\textbf{(A)  I and II}\qquad
+<math>\text{(A)  I and II}\qquad
-\textbf{(B)  I and III}\qquad
+\text{(B)  I and III}\qquad
-\textbf{(C)  I and IV} \\
+\text{(C)  I and IV} \quad \\
-\textbf{(D)  I, II, and III\qquad
+\text{(D)  I, II, and III} \qquad
-\textbf{(E)  I, II, and IV }</math>
+\text{(E)  I, II, and IV }</math>
 [[1972 AHSME Problems/Problem 1|Solution]]
@@ Line 21: / Line 24: @@
 == Problem 2 ==
-If a dealer could get his goods for <math>8\%</math> less while keeping his selling price fixed,
+If a dealer could get his goods for <math>8</math>% less while keeping his selling price fixed,
-his profit, based on cost, would be increased to <math>(x+10)\%</math> from his present profit of <math>x\%</math>, which is
+his profit, based on cost, would be increased to <math>(x+10)</math>% from his present profit of <math>x</math>%, which is
-<math></math>\textbf{(A) }12\%\qquad
+<math>\textbf{(A) }12\%\qquad
 \textbf{(B) }15\%\qquad
 \textbf{(C) }30\%\qquad
 \textbf{(D) }50\%\qquad
-\textbf{(E) }75\%     <math>
+\textbf{(E) }75\%     </math>
 [[1972 AHSME Problems/Problem 2|Solution]]
@@ Line 34: / Line 37: @@
 == Problem 3 ==
-If </math>x=\dfrac{1-i\sqrt{3}}{2}<math> where </math>i=\sqrt{-1}<math>, then </math>\dfrac{1}{x^2-x}<math> is equal to
+If <math>x=\dfrac{1-i\sqrt{3}}{2}</math> where <math>i=\sqrt{-1}</math>, then <math>\dfrac{1}{x^2-x}</math> is equal to
-</math><math>\textbf{(A) }-2\qquad
+<math>\textbf{(A) }-2\qquad
 \textbf{(B) }-1\qquad
 \textbf{(C) }1+i\sqrt{3}\qquad
@@ Line 65: / Line 68: @@
 \textbf{(C) } 3^{1/3},\ 9^{1/9}\quad
 \textbf{(D) } 8^{1/8},\ 9^{1/9}\quad \\
-\textbf{(E) None of these}</math>
+\text{(E) None of these}</math>
@@ Line 72: / Line 75: @@
 == Problem 6 ==
-If <math>3^{2x}+9=10\left(3^{x})\right</math>, then the value of <math>(x^2+1)</math> is
+If <math>3^{2x}+9=10\left(3^{x}\right)</math>, then the value of <math>(x^2+1)</math> is
 <math>\textbf{(A) }1\text{ only}\qquad
@@ Line 81: / Line 84: @@
 [[1972 AHSME Problems/Problem 6|Solution]]
 == Problem 7 ==
@@ Line 100: / Line 103: @@
 <math>\textbf{(A) }x=0\qquad
 \textbf{(B) }y=1\qquad
-\textbf{(C) }x=0\text{ and }y=1\qquad
+\textbf{(C) }x=0\text{ and }y=1\qquad\\
 \textbf{(D) }x(y-1)=0\qquad
 \textbf{(E) }\text{None of these} </math>
@@ Line 126: / Line 129: @@
 <math>\textbf{(A) }x\le 1\text{ or }x\ge 3\qquad
 \textbf{(B) }1\le x\le 3\qquad
-\textbf{(C) }-5\le x\le 9\qquad
+\textbf{(C) }-5\le x\le 9\qquad \\
 \textbf{(D) }-5\le x\le 1\text{ or }3\le x\le 9\qquad
 \textbf{(E) }-6\le x\le 1\text{ or }3\le x\le 10     </math>
@@ Line 297: / Line 300: @@
 <asy>
-draw((0,0)--(0,1)--(2,1)--(2,0)--cycle^^(.5,1)--(.5,2)--(1.5,2)--(1.5,1)--(.5,2)^^(.5,1)--(1.5,2)^^(1,2)--(1,0));
+draw((0,0)--(0,1)--(2,1)--(2,0)--cycle^^(.5,1)--(.5,2)--(1.5,2)--(1.5,1)--cycle^^(1,2)--(1,0));
-//Credit to Zimbalono for the diagram
 </asy>
@@ Line 310: / Line 312: @@
 [[1972 AHSME Problems/Problem 23|Solution]]
 == Problem 24 ==
-A man walked a certain distance at a constant rate. If he had gone \textstyle\frac{1}{2} mile per hour faster, he would have walked the distance in four-fifths of the time; if he had gone \textstyle\frac{1}{2} mile per hour slower, he would have been 2\textstyle\frac{1}{2} hours longer on the road. The distance in miles he walked was
+A man walked a certain distance at a constant rate. If he had gone <math>\textstyle\frac{1}{2}</math> mile per hour faster, he would have walked the distance in four-fifths of the time; if he had gone <math>\textstyle\frac{1}{2}</math> mile per hour slower, he would have been <math>2\textstyle\frac{1}{2}</math> hours longer on the road. The distance in miles he walked was
 <math>\textbf{(A) }13\textstyle\frac{1}{2}\qquad
@@ Line 325: / Line 327: @@
 == Problem 25 ==
-Inscribed in a circle is a quadrilateral having sides of lengths 25,~39,~52, and 60 taken consecutively. The diameter of this circle has length
+Inscribed in a circle is a quadrilateral having sides of lengths <math>25,~39,~52</math>, and <math>60</math> taken consecutively. The diameter of this circle has length
-$\textbf{(A) }62\qquad
+<math>\textbf{(A) }62\qquad
 \textbf{(B) }63\qquad
 \textbf{(C) }65\qquad
 \textbf{(D) }66\qquad
-\textbf{(E) }69
+\textbf{(E) }69   </math>
 [[1972 AHSME Problems/Problem 25|Solution]]
@@ Line 375: / Line 377: @@
 == Problem 28 ==
- A circular disc with diameter <math>D</math> is placed on an <math>8\times 8</math> checkerboard with width <math>D</math> so that the centers coincide.
+A circular disc with diameter <math>D</math> is placed on an <math>8\times 8</math> checkerboard with width <math>D</math> so that the centers coincide. The number of checkerboard squares which are completely covered by the disc is
- The number of checkerboard squares which are completely covered by the disc is
 <math>\textbf{(A) }48\qquad
@@ Line 393: / Line 394: @@
 \textbf{(B) }2f(x)\qquad
 \textbf{(C) }3f(x)\qquad
-\textbf{(D) }\left[f(x)\right]^2\qquad
+\textbf{(D) }\left[f(x)\right]^2\qquad \\
 \textbf{(E) }[f(x)]^3-f(x)    </math>
 [[1972 AHSME Problems/Problem 29|Solution]]
@@ Line 419: / Line 418: @@
 </asy>
-A rectangular piece of paper 6 inches wide is folded as in the diagram so that one corner touches the opposite side. The length in inches of the crease L in terms of angle \theta is
+A rectangular piece of paper 6 inches wide is folded as in the diagram so that one corner touches the opposite side. The length in inches of the crease L in terms of angle <math>\theta</math> is
 <math>\textbf{(A) }3\sec ^2\theta\csc\theta\qquad
@@ Line 429: / Line 428: @@
 [[1972 AHSME Problems/Problem 30|Solution]]
 == Problem 31 ==
@@ Line 522: / Line 521: @@
 [[1972 AHSME Problems/Problem 35|Solution]]
+== See also ==
+* [[AMC 12 Problems and Solutions]]
+* [[Mathematics competition resources]]
+{{AHSME 35p box|year=1972|before=[[1971 AHSME|1971 AHSC]]|after=Last AHSC, see [[1973 AHSME]]}}
+{{MAA Notice}}

1972 AHSC (Problems • Answer Key • Resources)
Preceded by 1971 AHSC	Followed by Last AHSC, see 1973 AHSME
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Difference between revisions of "1972 AHSME Problems"

Latest revision as of 23:21, 25 May 2024

Contents

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

See also