Difference between revisions of "1992 OIM Problems/Problem 6"

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== Problem ==
 
== Problem ==
 
From the triangle <math>T</math> with vertices <math>A</math>, <math>B</math> and <math>C</math>, the hexagon <math>H</math> with vertices <math>A_1</math>, <math>A_2</math>, <math>B_1</math>, <math>B_2</math>, <math>C_1</math>, <math>C_2</math> is constructed as shown in the figure.  
 
From the triangle <math>T</math> with vertices <math>A</math>, <math>B</math> and <math>C</math>, the hexagon <math>H</math> with vertices <math>A_1</math>, <math>A_2</math>, <math>B_1</math>, <math>B_2</math>, <math>C_1</math>, <math>C_2</math> is constructed as shown in the figure.  
 
[[File:ibe7_2.gif|center]]
 
  
 
Show that:
 
Show that:
  
 
<cmath>area(H) \ge 13.area(T)</cmath>
 
<cmath>area(H) \ge 13.area(T)</cmath>
 +
 +
[[File:ibe7_2.gif|center]]
  
 
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
 
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Revision as of 13:08, 13 December 2023

Problem

From the triangle $T$ with vertices $A$, $B$ and $C$, the hexagon $H$ with vertices $A_1$, $A_2$, $B_1$, $B_2$, $C_1$, $C_2$ is constructed as shown in the figure.

Show that:

\[area(H) \ge 13.area(T)\]

Ibe7 2.gif

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also

https://www.oma.org.ar/enunciados/ibe7.htm