Difference between revisions of "2023 AMC 12A Problems/Problem 7"
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− | + | ==Problem== | |
− | - | + | Janet rolls a standard <math>6</math>-sided die <math>4</math> times and keeps a running total of the numbers |
+ | she rolls. What is the probability that at some point, her running total will equal <math>3</math>? | ||
+ | |||
+ | ==Solution 1== | ||
+ | |||
+ | There are <math>4</math> cases where her running total can equal <math>3</math>: | ||
+ | 1. She rolled <math>1</math> for three times consecutively from the beginning. Probability: <math>frac{1}{6^3} = frac{1}{216} | ||
+ | 2. She rolled a </math>1<math>, then </math>2<math>. Probability: </math>frac{1}{6^2} = frac{1}{36} | ||
+ | 3. She rolled a <math>2</math>, then <math>1</math>. Probability: <math>frac{1}{6^2} = frac{1}{36} | ||
+ | 4. She rolled a </math>3<math> at the beginning. Probability: </math>frac{1}{6} | ||
+ | |||
+ | Add them together to get <math>\boxed{textbf{(B)} frac{49}{216}}</math> |
Revision as of 19:56, 9 November 2023
Problem
Janet rolls a standard -sided die times and keeps a running total of the numbers she rolls. What is the probability that at some point, her running total will equal ?
Solution 1
There are cases where her running total can equal : 1. She rolled for three times consecutively from the beginning. Probability: 12frac{1}{6^2} = frac{1}{36} 3. She rolled a , then . Probability: 3frac{1}{6}
Add them together to get