Difference between revisions of "User:Crazyvideogamez"
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# [https://artofproblemsolving.com/wiki/index.php/2019_AMC_10B_Problems/Problem_18#Solution_5_.28rigorous_unlike_all_the_other_solutions.2C_brief_use_of_rudimentary_limits.29 2019 AMC 10B Problems/Problem 18 Solution 5] (Combinatorics) | # [https://artofproblemsolving.com/wiki/index.php/2019_AMC_10B_Problems/Problem_18#Solution_5_.28rigorous_unlike_all_the_other_solutions.2C_brief_use_of_rudimentary_limits.29 2019 AMC 10B Problems/Problem 18 Solution 5] (Combinatorics) | ||
# [https://artofproblemsolving.com/wiki/index.php?title=2020_AMC_10A_Problems/Problem_24#Solution_12_.28does_not_require_ANY_guess_and_check.2C_Chinese_Remainder_Theorem.29 2020 AMC 10A Problems/Problem 24 Solution 12] (Number Theory) | # [https://artofproblemsolving.com/wiki/index.php?title=2020_AMC_10A_Problems/Problem_24#Solution_12_.28does_not_require_ANY_guess_and_check.2C_Chinese_Remainder_Theorem.29 2020 AMC 10A Problems/Problem 24 Solution 12] (Number Theory) | ||
| + | # [https://artofproblemsolving.com/wiki/index.php?title=2019_AMC_10B_Problems/Problem_25 2019 AMC 10B Problems/Problem 25 Solution 1] (Combinatorics) | ||
=== AIME === | === AIME === | ||
# [https://artofproblemsolving.com/wiki/index.php/2011_AIME_II_Problems/Problem_8#Solution_3 2011 AIME II Problems/Problem 8 Solution <math>1.\overline{6}</math>] (Complex Numbers) | # [https://artofproblemsolving.com/wiki/index.php/2011_AIME_II_Problems/Problem_8#Solution_3 2011 AIME II Problems/Problem 8 Solution <math>1.\overline{6}</math>] (Complex Numbers) | ||
Revision as of 16:41, 9 October 2023
AOPS Contributions
AMC
- 2019 AMC 10B Problems/Problem 18 Solution 5 (Combinatorics)
- 2020 AMC 10A Problems/Problem 24 Solution 12 (Number Theory)
- 2019 AMC 10B Problems/Problem 25 Solution 1 (Combinatorics)
AIME
- 2011 AIME II Problems/Problem 8 Solution
(Complex Numbers)
