Difference between revisions of "1968 AHSME Problems/Problem 16"

Revision as of 00:52, 16 August 2023

Problem

If $x$ is such that $\frac{1}{x}<2$ and $\frac{1}{x}>-3$ , then:

$\text{(A) } -\frac{1}{3}<x<\frac{1}{2}\quad \text{(B) } -\frac{1}{2}<x<3\quad \text{(C) } x>\frac{1}{2}\quad\\ \text{(D) } x>\frac{1}{2} \text{ or} -\frac{1}{3}<x<0\quad \text{(E) } x>\frac{1}{2} \text{ or } x<-\frac{1}{3}$

Solution

$\fbox{E}$

1968 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 15	Followed by Problem 17
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

@@ Line 13: / Line 13: @@
 == See also ==
-{{AHSME box|year=1968|num-b=15|num-a=17}}
+{{AHSME 35p box|year=1968|num-b=15|num-a=17}}
 [[Category: Introductory Algebra Problems]]
 {{MAA Notice}}

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Difference between revisions of "1968 AHSME Problems/Problem 16"

Revision as of 00:52, 16 August 2023

Problem

Solution

See also