Difference between revisions of "1968 AHSME Problems/Problem 2"

Revision as of 00:52, 16 August 2023

The real value of $x$ such that $64^{x-1}$ divided by $4^{x-1}$ equals $256^{2x}$ is:

$\text{(A) } -\frac{2}{3}\quad\text{(B) } -\frac{1}{3}\quad\text{(C) } 0\quad\text{(D) } \frac{1}{4}\quad\text{(E) } \frac{3}{8}$

$\fbox{B}$

1968 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35
All AHSME Problems and Solutions

@@ Line 12: / Line 12: @@
 == See also ==
-{{AHSME box|year=1968|num-b=1|num-a=3}}
+{{AHSME 35p box|year=1968|num-b=1|num-a=3}}
 [[Category: Introductory Algebra Problems]]
 {{MAA Notice}}