Difference between revisions of "1985 AJHSME Problem 13"
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https://youtu.be/varobXGlcdU | https://youtu.be/varobXGlcdU | ||
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Distance is equal to rate multiplied by time: | Distance is equal to rate multiplied by time: | ||
<cmath>d = \frac{45}{60} \cdot 4 + \frac{30}{60} \cdot 10 = \boxed{8}.</cmath> | <cmath>d = \frac{45}{60} \cdot 4 + \frac{30}{60} \cdot 10 = \boxed{8}.</cmath> | ||
The answer is <math>\text{(B)}.</math> | The answer is <math>\text{(B)}.</math> | ||
Latest revision as of 15:02, 4 July 2023
Problem
If you walk for 
minutes at a rate of 
and then run for 
minutes at a rate of 
how many miles will you have gone at the end of one hour and 
minutes?
In-depth Solution by BoundlessBrain!
Solution
Distance is equal to rate multiplied by time:
![\[d = \frac{45}{60} \cdot 4 + \frac{30}{60} \cdot 10 = \boxed{8}.\]](http://latex.artofproblemsolving.com/1/4/d/14dc9b0fee61d322a782528c39619e3acdd06fd1.png)
The answer is 
