Difference between revisions of "1985 AJHSME Problem 16"

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<math>\text{(A)}\ 10 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 6 \qquad \text{(E)}\ 2</math>
 
<math>\text{(A)}\ 10 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 6 \qquad \text{(E)}\ 2</math>
  
== Solution ==
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==In-depth Solution by BoundlessBrain!==
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https://youtu.be/LWBB5i_kmwE
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If there are <math>30</math> students in the class, there are <math>\frac{2}{2+3} \cdot 30 = 12</math> boys and <math>\frac{3}{2+3} \cdot 30 = 18</math> girls. So, there are <math>\boxed{\text{(D)} 6}</math> more girls than boys.
 
If there are <math>30</math> students in the class, there are <math>\frac{2}{2+3} \cdot 30 = 12</math> boys and <math>\frac{3}{2+3} \cdot 30 = 18</math> girls. So, there are <math>\boxed{\text{(D)} 6}</math> more girls than boys.

Revision as of 15:01, 4 July 2023

Problem

The ratio of boys to girls in Mr. Brown's math class is $2:3$. If there are $30$ students in the class, how many more girls than boys are in the class?

$\text{(A)}\ 10 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 6 \qquad \text{(E)}\ 2$

In-depth Solution by BoundlessBrain!

https://youtu.be/LWBB5i_kmwE

If there are $30$ students in the class, there are $\frac{2}{2+3} \cdot 30 = 12$ boys and $\frac{3}{2+3} \cdot 30 = 18$ girls. So, there are $\boxed{\text{(D)} 6}$ more girls than boys.