Difference between revisions of "2012 AMC 10A Problems/Problem 2"

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== Problem 2 ==
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== Problem ==
  
 
A square with side length 8 is cut in half, creating two congruent rectangles. What are the dimensions of one of these rectangles?
 
A square with side length 8 is cut in half, creating two congruent rectangles. What are the dimensions of one of these rectangles?
  
<math> \textbf{(A)}\ 2\ by\ 4\qquad\textbf{(B)}\ \ 2\ by\ 6\qquad\textbf{(C)}\ \ 2\ by\ 8\qquad\textbf{(D)}\ 4\ by\ 4\qquad\textbf{(E)}\ 4\ by\ 8 </math>
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<math> \textbf{(A)}\ 2\ \text{by}\ 4\qquad\textbf{(B)}\ \ 2\ \text{by}\ 6\qquad\textbf{(C)}\ \ 2\ \text{by}\ 8\qquad\textbf{(D)}\ 4\ \text{by}\ 4\qquad\textbf{(E)}\ 4\ \text{by}\ 8 </math>
  
 
== Solution ==
 
== Solution ==
  
Cutting the square in half will bisect one pair of sides while the other side will remain unchanged. Thus, the new square is <math>\frac{8}{2}*8</math>, or  <math>\qquad\textbf{(E)}\ 4*8</math>.
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Cutting the square in half will bisect one pair of sides while the other side will remain unchanged. Thus, the new square is <math>\frac{8}{2}</math> by <math>8</math>, or  <math>\boxed{\textbf{(E)}\ 4\ \text{by}\ 8}</math>.
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==Video Solution (CREATIVE THINKING)==
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https://youtu.be/ib6LCvSLo7M
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~Education, the Study of Everything
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== See Also ==
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{{AMC10 box|year=2012|ab=A|num-b=1|num-a=3}}
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{{MAA Notice}}

Latest revision as of 12:57, 1 July 2023

Problem

A square with side length 8 is cut in half, creating two congruent rectangles. What are the dimensions of one of these rectangles?

$\textbf{(A)}\ 2\ \text{by}\ 4\qquad\textbf{(B)}\ \ 2\ \text{by}\ 6\qquad\textbf{(C)}\ \ 2\ \text{by}\ 8\qquad\textbf{(D)}\ 4\ \text{by}\ 4\qquad\textbf{(E)}\ 4\ \text{by}\ 8$

Solution

Cutting the square in half will bisect one pair of sides while the other side will remain unchanged. Thus, the new square is $\frac{8}{2}$ by $8$, or $\boxed{\textbf{(E)}\ 4\ \text{by}\ 8}$.

Video Solution (CREATIVE THINKING)

https://youtu.be/ib6LCvSLo7M

~Education, the Study of Everything

See Also

2012 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AMC 10 Problems and Solutions

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