Difference between revisions of "2023 AMC 8 Problems/Problem 18"
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~Star League (https://starleague.us) | ~Star League (https://starleague.us) | ||
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| + | ==Video Solution by OmegaLearn (Using Restrictive Counting)== | ||
| + | https://youtu.be/gIjhiw1CUgY | ||
Revision as of 20:52, 24 January 2023
Solution
We have 
directions going 
right or 
left. We can assign a variable to each of these directions. We can call going right 1 direction X and we can call going 1 left Y. We can build a equation of 
. Where we have to limit the number of moves we do. We can do this by making more of our moves the move turn then the move turn. The first obvious step is to go some amount of moves in the → direction then subtract off in the ← direction to land on 
. The least amount of ’s added to to make a multiple of is 
as 
. So now we have solved the problem as we just go 
hops right, and just do 4 more hops left. Yielding 
as our answer.
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, lpieleanu
Animated Video Solution
~Star League (https://starleague.us)
