Difference between revisions of "2023 AMC 8 Problems/Problem 13"
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Knowing that there are <math>7</math> equally spaced water stations they are each located <math>\frac{d}{8}</math>, <math>\frac{2d}{8}</math>,… <math>\frac{7d}{8}</math> of the way from the start. Using the same logic for the <math>3</math> station we have <math>\frac{d}{3}</math> and <math>\frac{2d}{3}</math> for the repair stations. It is given that the 3rd water is <math>2</math> miles ahead of the <math>1</math>st repair station. So setting an equation we have <math>\frac{3d}{8} = \frac{d}{3} + 2</math> getting common denominators <math>\frac{9d}{24} = \frac{8d}{24} + 2</math> so then we have <math>d = \boxed{\text{(D)}48}</math> from this. | Knowing that there are <math>7</math> equally spaced water stations they are each located <math>\frac{d}{8}</math>, <math>\frac{2d}{8}</math>,… <math>\frac{7d}{8}</math> of the way from the start. Using the same logic for the <math>3</math> station we have <math>\frac{d}{3}</math> and <math>\frac{2d}{3}</math> for the repair stations. It is given that the 3rd water is <math>2</math> miles ahead of the <math>1</math>st repair station. So setting an equation we have <math>\frac{3d}{8} = \frac{d}{3} + 2</math> getting common denominators <math>\frac{9d}{24} = \frac{8d}{24} + 2</math> so then we have <math>d = \boxed{\text{(D)}48}</math> from this. | ||
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+ | ==Animated Video Solution== | ||
+ | https://youtu.be/NivfOThj1No | ||
+ | |||
+ | ~Star League (https://starleague.us) |
Revision as of 18:29, 24 January 2023
Knowing that there are equally spaced water stations they are each located , ,… of the way from the start. Using the same logic for the station we have and for the repair stations. It is given that the 3rd water is miles ahead of the st repair station. So setting an equation we have getting common denominators so then we have from this.
Animated Video Solution
~Star League (https://starleague.us)