Difference between revisions of "1993 UNCO Math Contest II Problems/Problem 2"
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== Problem == | == Problem == | ||
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| − | + | Fist we add them together and divide. We get the repeating decimal .134316134316. We can see that it repeats every six decimal places, so we need to find the remainder when 623 is divided by six. When we divide, we see that the remainder in five, so we go in five decimal places and find 1, and we are done. | |
| − | Fist we add them together and divide. We get the repeating decimal .134316134316. We can see that it repeats every six decimal places, so we need to find the remainder when 623 is divided by six. When we divide, we see that the remainder | ||
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== See also == | == See also == | ||
Revision as of 23:24, 19 January 2023
Problem
Determine the digit in the 
place after the decimal point in the repeating decimal for:
![\[\frac{1}{9}+\frac{2}{99}+\frac{3}{999}.\]](http://latex.artofproblemsolving.com/3/8/7/387a5a2b63baa05702f1c04e43386006d0f7cd42.png)
Solution
Fist we add them together and divide. We get the repeating decimal .134316134316. We can see that it repeats every six decimal places, so we need to find the remainder when 623 is divided by six. When we divide, we see that the remainder in five, so we go in five decimal places and find 1, and we are done.
See also
| 1993 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
| All UNCO Math Contest Problems and Solutions | ||
