Difference between revisions of "2018 AMC 8 Problems/Problem 19"
m (→Solution 4: Deleted circular-logic solution) |
m (→Solution 2: rewrote incoherent explanation.) |
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==Solution 2== | ==Solution 2== | ||
− | The | + | The top box is fixed by the problem. |
+ | |||
+ | Choose the left 3 bottom-row boxes freely. There are <math>2^3=8</math> ways. | ||
+ | |||
+ | Then the left 2 boxes on the row above are determined. | ||
+ | |||
+ | Then the left 1 box on the row above that is determined | ||
+ | |||
+ | Then the right 1 box on that row is determined. | ||
+ | |||
+ | Then the right 1 box on the row below is determined. | ||
+ | |||
+ | Then the right 1 box on the bottom row is determined, completing the diagram. | ||
+ | |||
+ | So the answer is <math>\boxed{\textbf{(C) } 8}</math>. | ||
+ | |||
+ | |||
+ | ~BraveCobra22aops | ||
==Video Solution== | ==Video Solution== |
Revision as of 20:50, 1 January 2023
Problem
In a sign pyramid a cell gets a "+" if the two cells below it have the same sign, and it gets a "-" if the two cells below it have different signs. The diagram below illustrates a sign pyramid with four levels. How many possible ways are there to fill the four cells in the bottom row to produce a "+" at the top of the pyramid?
Solution 1
You could just make out all of the patterns that make the top positive. In this case, you would have the following patterns:
+−−+, −++−, −−−−, ++++, −+−+, +−+−, ++−−, −−++. There are 8 patterns and so the answer is .
-NinjaBoi2000
Solution 2
The top box is fixed by the problem.
Choose the left 3 bottom-row boxes freely. There are ways.
Then the left 2 boxes on the row above are determined.
Then the left 1 box on the row above that is determined
Then the right 1 box on that row is determined.
Then the right 1 box on the row below is determined.
Then the right 1 box on the bottom row is determined, completing the diagram.
So the answer is .
~BraveCobra22aops
Video Solution
~savannahsolver
See Also
2018 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.