Difference between revisions of "2008 AMC 8 Problems/Problem 1"
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\textbf{(B)}\ 14 \qquad | \textbf{(B)}\ 14 \qquad | ||
\textbf{(C)}\ 26 \qquad | \textbf{(C)}\ 26 \qquad | ||
| − | \textbf{(D)}\ 38 \qquad</math> | + | \textbf{(D)}\ 38 \qquad |
| + | \textbf{(E)}\ 50</math> | ||
==Solution== | ==Solution== | ||
| − | If Susan spent 12 dollars, then twice that much on rides, then she spent <math>36</math> dollars in total. We subtract <math>36</math> from <math>50</math> to get <math>\boxed{\textbf{(B)}\ 14}</math> | + | If Susan spent 12 dollars, then twice that much on rides, then she spent <math>12+12 \times 2=36</math> dollars in total. We subtract <math>36</math> from <math>50</math> to get <math>\boxed{\textbf{(B)}\ 14}</math> |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2008|before=First Problem|num-a=2}} | {{AMC8 box|year=2008|before=First Problem|num-a=2}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 16:52, 6 November 2022
Problem
Susan had 50 dollars to spend at the carnival. She spent 12 dollars on food and twice as much on rides. How many dollars did she have left to spend?
Solution
If Susan spent 12 dollars, then twice that much on rides, then she spent 
dollars in total. We subtract 
from 
to get 
See Also
| 2008 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
