Difference between revisions of "1982 AHSME Problems/Problem 1"
(→Solution 2) |
|||
| Line 17: | Line 17: | ||
Substituting an easy value, like <math>3</math>, you get <math>\frac{25}{7}</math>, with a remainder of 4. Then you just plug in x to get <math>E</math> | Substituting an easy value, like <math>3</math>, you get <math>\frac{25}{7}</math>, with a remainder of 4. Then you just plug in x to get <math>E</math> | ||
| + | |||
| + | -dragoon | ||
==See Also== | ==See Also== | ||
Latest revision as of 11:27, 10 October 2022
Contents
Problem
When the polynomial 
is divided by the polynomial 
, the remainder is
Solution
Working out 
using polynomial long division, we get 
.
Thus the answer is 
, for choice 
.
Solution 2
Substituting an easy value, like 
, you get 
, with a remainder of 4. Then you just plug in x to get 
-dragoon
See Also
| 1982 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
