Difference between revisions of "2005 PMWC Problems/Problem I14"

(Problem)
(Problem)
 
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== Problem ==
 
George purchases a sack of apples, a bunch of bananas, a cantaloupe, and a carton of dates for <math> \$ 20</math>. If a carton of dates costs twice as much as a sack of apples and the price of a cantaloupe is equal to the price of a sack of apples minus a bunch of bananas, how much would it cost George to purchase a bunch of bananas and a cantaloupe?
 
 
 
== Solution ==
 
== Solution ==
 
From the given, we have the [[equation]]s
 
From the given, we have the [[equation]]s

Latest revision as of 20:33, 21 August 2022

Solution

From the given, we have the equations

\[3g = 6b \Longrightarrow g = 2b\] \[2y = 5b \Longrightarrow y = \frac{5}{2}b\] \[4w = 6b \Longrightarrow w = \frac{3}{2}b\]

Substuting gives us $4g + 2y + 2w = 4(2b) + 2\left(\frac{5}{2}b\right) + 2\left(\frac{3}{2}b\right) = 16b$, and our answer is 16.

See also

2005 PMWC (Problems)
Preceded by
Problem I13
Followed by
Problem I15
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10