Difference between revisions of "2020 AMC 8 Problems/Problem 2"
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| − | == | + | ==Easy Probs.com== |
| − | 4 friends do | + | 4 friends do som deed to neighbor over weekend, earning <math>\$15, \$20, \$25,</math> and <math>\$40,</math> respectively. The Friends decide to split earnings equally among themselves. In total how much will friend who earned <math>\$40</math> give to other friends? |
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<math>\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25</math>s | <math>\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25</math>s | ||
Revision as of 11:44, 4 December 2021
Contents
Easy Probs.com
4 friends do som deed to neighbor over weekend, earning 
and 
respectively. The Friends decide to split earnings equally among themselves. In total how much will friend who earned 
give to other friends?
s
Solution
The friends earn 
in total. Since they decided to split their earnings equally, it follows that each person will get 
. Since the friend who earned will need to leave with 
, he will have to give 
to the others.
Video Solution by WhyMath
~savannahsolver
Video Solution by North America Math Contest Go Go Go
https://www.youtube.com/watch?v=ZwfPEYd55NQ
~North America Math Contest Go Go Go
Video Solution
Video Solution by Interstigation
https://youtu.be/YnwkBZTv5Fw?t=62
~Interstigation
See also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
