Difference between revisions of "2021 Fall AMC 10B Problems/Problem 4"
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<math>(\textbf{A})\: 10\qquad(\textbf{B}) \: 30\qquad(\textbf{C}) \: 60\qquad(\textbf{D}) \: 100\qquad(\textbf{E}) \: 120</math> | <math>(\textbf{A})\: 10\qquad(\textbf{B}) \: 30\qquad(\textbf{C}) \: 60\qquad(\textbf{D}) \: 100\qquad(\textbf{E}) \: 120</math> | ||
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+ | ==Solution== | ||
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+ | Let the temperature of Minneapolis at noon be <math>M</math> and let the temperature of St. Louis at noon be <math>S</math>. Then <math>M = N + S</math> and <math>(M-5)-(S+3) = |2| \implies M-S-8 = |2|</math>. | ||
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+ | Substituting <math>M</math> into the second equation we have <math>N - 8</math> = |2| \implies N = 10, 6<math>. | ||
+ | |||
+ | The product of all possible values of N is therefore </math>10\cdot6=60=\boxed{C} | ||
+ | |||
+ | ~KingRavi |
Revision as of 23:48, 22 November 2021
At noon on a certain day, Minneapolis is degrees warmer than St. Louis. At the temperature in Minneapolis has fallen by degrees while the temperature in St. Louis has risen by degrees, at which time the temperatures in the two cities differ by degrees. What is the product of all possible values of
Solution
Let the temperature of Minneapolis at noon be and let the temperature of St. Louis at noon be . Then and .
Substituting into the second equation we have = |2| \implies N = 10, 6$.
The product of all possible values of N is therefore$ (Error compiling LaTeX. Unknown error_msg)10\cdot6=60=\boxed{C}
~KingRavi