Difference between revisions of "User:Temperal/Introductory Proportion"

(Problem)
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==Problem==
 
==Problem==
Suppose <math>\displaystyle \frac{1}{20}</math> is either '''x''' or '''y''' in the following system:<br />
+
Suppose <math>\frac{1}{20}</math> is either '''x''' or '''y''' in the following system:
:<math>\begin{cases}
+
<cmath>\begin{cases}
 
xy=\frac{1}{k}\\
 
xy=\frac{1}{k}\\
 
x=ky
 
x=ky
\end{cases}</math> <br />
+
\end{cases}. </cmath>
 
Find the possible values of '''k'''.
 
Find the possible values of '''k'''.
  

Revision as of 15:23, 20 September 2007

Problem

Suppose $\frac{1}{20}$ is either x or y in the following system: \[\begin{cases} xy=\frac{1}{k}\\ x=ky \end{cases}.\] Find the possible values of k.

Solution

Template:Incomplete If $x=\frac{1} {20}$, then $\displaystyle  \frac{y} {20} = \frac{1} {k}$.