Difference between revisions of "2003 AIME II Problems"
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== Problem 2 == | == Problem 2 == | ||
+ | Let <math>N</math> be the greastest integer multiple of 8, no two whose digits are the same. What is the remainder when <math>N</math> is divided by 1000. | ||
[[2003 AIME II Problems/Problem 2|Solution]] | [[2003 AIME II Problems/Problem 2|Solution]] |
Revision as of 13:34, 15 September 2007
Contents
Problem 1
The product of three positive integers is 6 times their sum, and one of the integers is the sum of the other two. Find the sum of all possible values of .
Problem 2
Let be the greastest integer multiple of 8, no two whose digits are the same. What is the remainder when is divided by 1000.