Difference between revisions of "Quadratic equation"

 
(9 intermediate revisions by 6 users not shown)
Line 1: Line 1:
A '''quadratic equation''' is an [[equation]] of the form <math> {a}{x}^2+{b}{x}+{c}=0</math>. a, b, and c are [[constant]]s, and x is the unknown [[variable]]. Quadratic equations are solved using 3 main strategies: [[factoring]], [[completing the square]], and the [[quadratic formula]].
+
A '''quadratic equation''' in one [[variable]] is an [[equation]] of the form <math> {a}{x}^2+{b}{x}+{c}=0</math>, where <math>a</math>, <math>b</math> and <math>c</math> are [[constant]]s (that is, they do not depend on <math>x</math>) and <math>x</math> is the unknown variable. Quadratic equations are solved using one of three main strategies: [[factoring]], [[completing the square]] and the [[quadratic formula]].
 
 
  
 
=== Factoring ===
 
=== Factoring ===
 
 
The purpose of factoring is to turn a general quadratic into a product of [[binomial]]s. This is easier to illustrate than to describe.
 
The purpose of factoring is to turn a general quadratic into a product of [[binomial]]s. This is easier to illustrate than to describe.
  
Line 14: Line 12:
 
Next, we factor out our common terms to get <math>x(x-1)-2(x-1)=0</math>.
 
Next, we factor out our common terms to get <math>x(x-1)-2(x-1)=0</math>.
  
We can now factor the <math>(x-1)</math> term to get <math>(x-1)(x-2)=0</math>. By a well known theorem, either <math> (x-1) </math> or <math> (x-2) </math> equals zero.  
+
We can now factor the <math>(x-1)</math> term to get <math>(x-1)(x-2)=0</math>. By the zero-product property, either <math> (x-1) </math> or <math> (x-2) </math> equals zero.  
  
 
We now have the pair of equations <math>x-1=0</math> and <math>x-2=0</math>. These give us the answers <math>x=1</math> and <math>x=2</math>, which can also be written as <math>x=\{1,\,2\}</math>. Plugging these back into the original equation, we find that both of these work! We are done.
 
We now have the pair of equations <math>x-1=0</math> and <math>x-2=0</math>. These give us the answers <math>x=1</math> and <math>x=2</math>, which can also be written as <math>x=\{1,\,2\}</math>. Plugging these back into the original equation, we find that both of these work! We are done.
 
  
 
=== Completing the square ===
 
=== Completing the square ===
Line 27: Line 24:
 
== See Also ==
 
== See Also ==
 
* [[Discriminant]]
 
* [[Discriminant]]
 +
* [[Vieta's Formulas]]
 
* [[Quadratic Inequality]]
 
* [[Quadratic Inequality]]
 +
* [[Factoring Quadratics]]
 +
 +
[[Category:Algebra]]
 +
[[Category:Quadratic equations]]
 +
[[Category:Definition]]

Latest revision as of 11:04, 15 July 2021

A quadratic equation in one variable is an equation of the form ${a}{x}^2+{b}{x}+{c}=0$, where $a$, $b$ and $c$ are constants (that is, they do not depend on $x$) and $x$ is the unknown variable. Quadratic equations are solved using one of three main strategies: factoring, completing the square and the quadratic formula.

Factoring

The purpose of factoring is to turn a general quadratic into a product of binomials. This is easier to illustrate than to describe.

Example: Solve the equation $x^2-3x+2=0$ for $x$. Note: This is different for all quadratics; we cleverly chose this so that it has common factors.

Solution: $x^2-3x+2=0$

First, we expand the middle term: $x^2-x-2x+2=0$.

Next, we factor out our common terms to get $x(x-1)-2(x-1)=0$.

We can now factor the $(x-1)$ term to get $(x-1)(x-2)=0$. By the zero-product property, either $(x-1)$ or $(x-2)$ equals zero.

We now have the pair of equations $x-1=0$ and $x-2=0$. These give us the answers $x=1$ and $x=2$, which can also be written as $x=\{1,\,2\}$. Plugging these back into the original equation, we find that both of these work! We are done.

Completing the square

Completing the square

Quadratic Formula

See Quadratic Formula.

See Also