Difference between revisions of "2004 AMC 10A Problems/Problem 1"
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==Solution== | ==Solution== | ||
| − | There are 6 people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars. <math>\Rightarrow\mathrm{( | + | There are <math>6</math> people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars. <math>\Rightarrow\boxed{\mathrm{(A)}\ 250}</math> |
| − | == | + | ==Video Solution == |
| − | + | https://youtu.be/_O3a6-sSgvc | |
| − | + | Education, the Study of Everything | |
| + | |||
| + | == See also == | ||
| + | {{AMC10 box|year=2004|ab=A|before=First Question|num-a=2}} | ||
| + | |||
| + | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 13:13, 21 April 2021
Contents
Problem
You and five friends need to raise 
dollars in donations for a charity, dividing the fundraising equally. How many dollars will each of you need to raise?
Solution
There are 
people to split the dollars among, so each person must raise 
dollars. 
Video Solution
Education, the Study of Everything
See also
| 2004 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
