Difference between revisions of "2008 AMC 8 Problems/Problem 5"
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==Solution== | ==Solution== | ||
| − | Barney travels <math>1661-1441=220</math> miles in | + | Barney travels <math>1661-1441=220</math> miles in 6=10<math> hours for an average of </math>220/10=\boxed{\textbf{(E)}\ 22}$ miles per hour. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2008|num-b=4|num-a=6}} | {{AMC8 box|year=2008|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 12:26, 27 March 2021
Problem
Barney Schwinn notices that the odometer on his bicycle reads 
, a palindrome, because it reads the same forward and backward. After riding more hours that day and 
the next, he notices that the odometer shows another palindrome, 
. What was his average speed in miles per hour?
Solution
Barney travels 
miles in 6=10
220/10=\boxed{\textbf{(E)}\ 22}$ miles per hour.
See Also
| 2008 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
