Difference between revisions of "2007 Cyprus MO/Lyceum/Problem 2"

Revision as of 16:54, 6 May 2007

Given the formula $f(x) = 4^x$ , then $f(x+1)-f(x)$ equals to

$\mathrm{(A) \ } 4\qquad \mathrm{(B) \ } 4^x\qquad \mathrm{(C) \ } 2\cdot4^x\qquad \mathrm{(D) \ } 4^{x+1}\qquad \mathrm{(E) \ } 3\cdot4^x$

$f(x+1)-f(x)=4^{x+1}-4^x=4\cdot4^x-4^x=(4-1)\cdot4^x=3\cdot4^x\Rightarrow\mathrm{ E}$

Revision as of 15:16, 6 May 2007 (view source) Azjps (talk \| contribs) m (→‎See also: +) ← Older edit		Revision as of 16:54, 6 May 2007 (view source) Azjps (talk \| contribs) m (→‎See also: intro) Newer edit →
Line 10:		Line 10:
	{{CYMO box\|year=2007\|l=Lyceum\|num-b=1\|num-a=3}}		{{CYMO box\|year=2007\|l=Lyceum\|num-b=1\|num-a=3}}

−	[[Category:~~Intermediate~~ Algebra Problems]]	+	[[Category:Introductory Algebra Problems]]