Difference between revisions of "1955 AHSME Problems/Problem 10"
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The train will take <math>\frac{a}{40}</math> hours to travel <math>a</math> miles, and it takes <math>\frac{nm}{60}</math>. The LCM of <math>40</math> and <math>60</math> is <math>120</math>, which allows for the addition of the fractions <math>\frac{3a}{120}</math> and <math>\frac{2mn}{120}</math>. The end result is <math>\boxed{\textbf{(A)}\frac{3a+2mn}{120}}</math>. | The train will take <math>\frac{a}{40}</math> hours to travel <math>a</math> miles, and it takes <math>\frac{nm}{60}</math>. The LCM of <math>40</math> and <math>60</math> is <math>120</math>, which allows for the addition of the fractions <math>\frac{3a}{120}</math> and <math>\frac{2mn}{120}</math>. The end result is <math>\boxed{\textbf{(A)}\frac{3a+2mn}{120}}</math>. | ||
==See Also== | ==See Also== | ||
| − | + | == See Also == | |
| + | {{AHSME 50p box|year=1955|num-b=9|num-a=1}} | ||
| − | {{MAA Notice | + | {{MAA Notice} |
Revision as of 09:40, 15 February 2021
How many hours does it take a train traveling at an average rate of 40 mph between stops to travel a miles it makes n stops of m minutes each?
Solution
The train will take 
hours to travel 
miles, and it takes 
. The LCM of 
and 
is 
, which allows for the addition of the fractions 
and 
. The end result is 
.
See Also
See Also
| 1955 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 1 | |
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| All AHSME Problems and Solutions | ||
{{MAA Notice}
