Difference between revisions of "1984 AJHSME Problem 9"

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-== Solution ==
-This product simplifies to:
-<cmath>\frac{1}{2} \cdot \frac{2}{3} \dots \frac{9}{10}.</cmath>
-Numerators and denominators cancel to yield the answer: <math>\boxed{\text{(A)} \frac{1}{10}}.</math>

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