Difference between revisions of "2020 AMC 8 Problems/Problem 3"
(→See also) |
|||
| Line 7: | Line 7: | ||
The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is <math>6 \times 8 \times 10 \times 4 = 1920</math> or <math>\boxed{\textbf{D }1920}</math>. | The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is <math>6 \times 8 \times 10 \times 4 = 1920</math> or <math>\boxed{\textbf{D }1920}</math>. | ||
| − | ==See also== | + | ==See also== |
| − | {{AMC8 box|year=2020| | + | {{AMC8 box|year=2020|num-b=2|num-a=4}} |
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 00:34, 18 November 2020
Problem 3
Carrie has a rectangular garden that measures 
feet by 
feet. She plants the entire garden with strawberry plants. Carrie is able to plant 
strawberry plants per square foot, and she harvests an average of 
strawberries per plant. How many strawberries can she expect to harvest?
Solution
The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is 
or 
.
See also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
