Difference between revisions of "2020 AMC 8 Problems/Problem 5"
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<math>\textbf{(A) }5 \qquad \textbf{(B) }10 \qquad \textbf{(C) }15 \qquad \textbf{(D) }20 \qquad \textbf{(E) }25</math> | <math>\textbf{(A) }5 \qquad \textbf{(B) }10 \qquad \textbf{(C) }15 \qquad \textbf{(D) }20 \qquad \textbf{(E) }25</math> | ||
| + | ==Solution== | ||
| + | To equally distribute to <math>5</math> cups, we will simply divide <math>\dfrac{3}{4}</math> by <math>5.</math> Simplifying, we get: <math>\dfrac{3}{4} \cdot \dfrac{1}{5} = \dfrac{3}{20}.</math> Converting that into a percent, we get an answer of <math>\boxed{\textbf{(C) }15}</math> | ||
==See also== | ==See also== | ||
{{AMC8 box|year=2020|before=First problem|num-a=2}} | {{AMC8 box|year=2020|before=First problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 00:17, 18 November 2020
Problem 5
Three fourths of a pitcher is filled with pineapple juice. The pitcher is emptied by pouring an equal amount of juice into each of 
cups. What percent of the total capacity of the pitcher did each cup receive?
Solution
To equally distribute to cups, we will simply divide 
by 
Simplifying, we get: 
Converting that into a percent, we get an answer of 
See also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
