Difference between revisions of "2020 AMC 8 Problems/Problem 12"

(Created page with "Solution 1 Notice that <math>5!</math> = <math>2*3*4*5,</math> and we can combine the numbers to make a bigger factorial. To change <math>9!</math> to <math>10!,</math> we ne...")
 
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<cmath>10!=N!.</cmath>
 
<cmath>10!=N!.</cmath>
 
Thus, <math>N=10(A).</math>
 
Thus, <math>N=10(A).</math>
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-iiRishabii

Revision as of 23:53, 17 November 2020

Solution 1

Notice that $5!$ = $2*3*4*5,$ and we can combine the numbers to make a bigger factorial. To change $9!$ to $10!,$ we need to multiply $9!$ by $2*5,$ which equals $10!.$ Therefore, we have

\[10!*12=12*N!.\] After canceling the $12s,$ we have

\[10!=N!.\] Thus, $N=10(A).$

-iiRishabii