Difference between revisions of "1957 AHSME Problems/Problem 7"
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<math>\textbf{(A)}\ 72\sqrt{3} \qquad \textbf{(B)}\ 48\sqrt{3}\qquad \textbf{(C)}\ 36\qquad \textbf{(D)}\ 24\qquad \textbf{(E)}\ 72 </math> | <math>\textbf{(A)}\ 72\sqrt{3} \qquad \textbf{(B)}\ 48\sqrt{3}\qquad \textbf{(C)}\ 36\qquad \textbf{(D)}\ 24\qquad \textbf{(E)}\ 72 </math> | ||
==Solution== | ==Solution== | ||
| + | <asy> | ||
| + | draw((-3,-sqrt(3))--(3,-sqrt(3))--(0,2sqrt(3))--cycle); | ||
| + | draw(circle((0,0),sqrt(3))); | ||
| + | dot((0,0)); | ||
| + | </asy> | ||
==See Also== | ==See Also== | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 11:06, 12 October 2020
Problem 7
The area of a circle inscribed in an equilateral triangle is 
. The perimeter of this triangle is:
Solution
![[asy] draw((-3,-sqrt(3))--(3,-sqrt(3))--(0,2sqrt(3))--cycle); draw(circle((0,0),sqrt(3))); dot((0,0)); [/asy]](http://latex.artofproblemsolving.com/f/1/c/f1c16c80859031202c30e32421aa94a6c34e8ad4.png)
See Also
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
