Difference between revisions of "User:CreativeHedgehog/Templates/2 var linear equation"

(Created page with "<noinclude> {{User:CreativeHedgehog/Templates/Navbar||||||||20px}} </noinclude> given a, b, c, d, e, and f, find x and y in the 2 equations below: {{{a}}}x+{{{b}}}y={{{c}}...")
 
 
(One intermediate revision by the same user not shown)
Line 7: Line 7:
 
given a, b, c, d, e, and f, find x and y in the 2 equations below:
 
given a, b, c, d, e, and f, find x and y in the 2 equations below:
  
{{{a}}}x+{{{b}}}y={{{c}}}
+
{{{a}}}x+{{{b}}}y={{{e}}}
  
{{{d}}}x+{{{e}}}y={{{f}}}
+
{{{c}}}x+{{{d}}}y={{{f}}}
  
 
x=({{{e}}}*{{{d}}}-{{{b}}}*{{{f}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})
 
x=({{{e}}}*{{{d}}}-{{{b}}}*{{{f}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})
Line 16: Line 16:
  
 
<noinclude>
 
<noinclude>
{{User:CreativeHedgehog/Templates/2 var linear equation|c=25|b=34|a=57|d=23|e=35|f=57}}
+
{{User:CreativeHedgehog/Templates/2 var linear equation|c=2|b=2|a=4|d=4|e=1|f=0}}
 +
Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 14:42, 7 August 2020 (EDT)
  
Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 14:42, 7 August 2020 (EDT)
+
It is not fully correct, and I am fixing its bugs. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 15:59, 8 August 2020 (EDT)
 
</noinclude>
 
</noinclude>

Latest revision as of 14:59, 8 August 2020


p




Social Media by CreativeHedgehog avatar.jpg


CreativeHedgehog avatar.jpg


given a, b, c, d, e, and f, find x and y in the 2 equations below:

{{{a}}}x+{{{b}}}y={{{e}}}

{{{c}}}x+{{{d}}}y={{{f}}}

x=({{{e}}}*{{{d}}}-{{{b}}}*{{{f}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})

y=({{{a}}}*{{{f}}}-{{{e}}}*{{{c}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})



given a, b, c, d, e, and f, find x and y in the 2 equations below:

4x+2y=1

2x+4y=0

x=(1*4-2*0)/(4*4-2*2)

y=(4*0-1*2)/(4*4-2*2)


Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. CreativeHedgehog 14:42, 7 August 2020 (EDT)

It is not fully correct, and I am fixing its bugs. CreativeHedgehog 15:59, 8 August 2020 (EDT)