Difference between revisions of "2020 AMC 10A Problems/Problem 1"
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==Problem== | ==Problem== | ||
| − | What value of <math>x</math> satisfies <cmath>x- \frac{ | + | What value of <math>x</math> satisfies <cmath>x- \frac{3}{4} = \frac{5}{12} - \frac{1}{3}?</cmath> |
<math>\textbf{(A)}\ -\frac{2}{3}\qquad\textbf{(B)}\ \frac{7}{36}\qquad\textbf{(C)}\ \frac{7}{12}\qquad\textbf{(D)}\ \frac{2}{3}\qquad\textbf{(E)}\ \frac{5}{6}</math> | <math>\textbf{(A)}\ -\frac{2}{3}\qquad\textbf{(B)}\ \frac{7}{36}\qquad\textbf{(C)}\ \frac{7}{12}\qquad\textbf{(D)}\ \frac{2}{3}\qquad\textbf{(E)}\ \frac{5}{6}</math> | ||
Revision as of 01:47, 11 April 2020
Contents
Problem
What value of 
satisfies ![\[x- \frac{3}{4} = \frac{5}{12} - \frac{1}{3}?\]](http://latex.artofproblemsolving.com/5/b/f/5bfe02ab9c82120a6496887cf9a11c3438b9be67.png)
Solution
Adding 
to both sides, 
.
Video Solution
~IceMatrix
See Also
| 2020 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
