Difference between revisions of "2020 AMC 12B Problems/Problem 25"
(→Problem 25) |
(→Solution) |
||
Line 9: | Line 9: | ||
==Solution== | ==Solution== | ||
+ | |||
+ | Let's start first by manipulating the given inequality. | ||
+ | |||
+ | <cmath>\sin^{2}{(\pi x)}+\sin^{2}{(\pi y)}>1</cmath> | ||
+ | <cmath>\sin^{2}{\pi x}>1-\sin^{2}{\pi y}=\cos^{2}{\pi y}</cmath> | ||
+ | |||
+ | Let's consider the boundary cases: <math>\sin^{2}{\pi x}=\cos^{2}{\pi y}</math> and <math>\sin^{2}{\pi x}=-\cos^{2}{\pi y}</math> |
Revision as of 23:34, 7 February 2020
Problem 25
For each real number with , let numbers and be chosen independently at random from the intervals and , respectively, and let be the probability that
What is the maximum value of
Solution
Let's start first by manipulating the given inequality.
Let's consider the boundary cases: and